replacing with NA
x[is.na(z)] <- NA This might send you a nasty bug if x and z are different lengths though -- just a head's up. Michael On Wed, May 16, 2012 at 12:55 PM, Mintewab Bezabih
<Mintewab.Bezabih at economics.gu.se> wrote:
Dear R users, I was wondering ?how I can replace the values of a vector with the values from in another vector in the same row For example, how can I replace the value of x below with NA when the value of Z in the same row is NA? x <-1:20 z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16,17, NA, 12, 10) Many thanks Mintewab
________________________________________ Fr?n: Mintewab Bezabih Skickat: den 15 maj 2012 15:53 Till: r-help at r-project.org Kopia: r-help at r-project.org ?mne: missing observations Dear R users, I have missing observations in my data that I remove in my analysis. I am able to run my codes alright but I want the non missing values to be correctly identified and therefore want to tag my id vector along in my results. Since the vector of ids has no role in the analysis, I dont know how to include it. Here is my reprducable example:and my id is the vector I want to add to the analysis somehow so that my missing values are identified. I cannot use ?na.action function and that is why I have to drop my missing obesevations beforehand. library(fields) x <-1:20 y<- runif(20) z<- c(11, 15, 17, 2, 18, 6, 7, NA, 12, 10,21, 25, 27, 12, 28, 16, 17, NA, 12, 10) id <-1:20 mydataset<-data.frame(x, y, z) temperature[complete.cases(mydataset),] ?x<- temperature[, c(1)] y<- temperature[, c(2)] z<- temperature[, c(3)] tpsfit <- Tps(cbind(x, y), z, scale.type="unscaled") Many thanks as always. Regards, Mintewab ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.