Multivariate EWMA covariance estimator?
On 02-06-2013, at 19:03, Neuman Co <neumancohu at gmail.com> wrote:
Thanks a lot for your answer, one more question: I now use 100 values, so not infinity values. That means I cut some values off, so the weights will not sum up to one. With which factor do I have to multiply the (1-lambda)*summe2 to rescale it? So that I do not always underestimate the variance anymore?
I don't know but maybe something like this 1/sum(lambda^((1:100)-1))/(1-lambda) which in your case is 1.000027 Berend
2013/6/2 Berend Hasselman <bhh at xs4all.nl>:
On 02-06-2013, at 15:17, Neuman Co <neumancohu at gmail.com> wrote:
Hi,
since I want to calculate the VaR of a portfolio consiting of 4 assets
(returns saved into "eonreturn","henkelreturn" and so on) I have to
estimate the covariance matrix. I do not want to take the rectangular
version with equal weights, but the exponentially weighted moving
average in a multivariate version. I want to estimate a covariance
matrix at every time point t. Then I want to comput the VaR at this
time point t. Afterwards, I will look at the exceedances and do a
backtest.
I tried to implement it as follows (data attached):
lambda<-0.9
summe2<-0
dummy2<-0
covestiexpo<-list(NA)
meanvalues<-NA
for(i in 101:length(eonreturn)){
meanvalues<-matrix(c(mean(eonreturn[(i-100):(i-1)]),mean(henkelreturn[(i-100):(i-1)]),mean(siemensreturn[(i-100):(i-1)]),mean(adidasreturn[(i-100):(i-1)])),4)
for(a in 1:100){
dummy2<-lambda^(a-1)*t(datamatrix[(i-a),]-t(meanvalues))%*%(datamatrix[(i-a),]-t(meanvalues))
summe2<-summe2+dummy2
}
covestiexpo[[i]]<-(1-lambda)*summe2
}
So the covestieexpo[[101]] would be the covariance estimate for the
101th day, taking into account the last 100 observations. Now, the
problem is, that there seems to be something wrong, since the
covariance estimates are cleraly wrong, they seem to be too big. At
the beginning, compared to the normal covariance estimate the
difference is as follows:
covestiexpo[[101]]
[,1] [,2] [,3] [,4]
[1,] 0.004559042 0.002346775 0.004379735 0.003068916
[2,] 0.002346775 0.001978469 0.002536891 0.001909276
[3,] 0.004379735 0.002536891 0.005531590 0.003259803
[4,] 0.003068916 0.001909276 0.003259803 0.003140198
compared to cov(datamatrix[1:100,])
[,1] [,2] [,3] [,4]
[1,] 0.0018118239 0.0007432779 0.0015301070 0.001119120
[2,] 0.0007432779 0.0008355960 0.0009281029 0.000754449
[3,] 0.0015301070 0.0009281029 0.0021073171 0.001269626
[4,] 0.0011191199 0.0007544490 0.0012696257 0.001325716
So already here, it is obvious, that something is not correct, if I
look at a period far ahead:
covestiexpo[[1200]]
[,1] [,2] [,3] [,4]
[1,] 0.5312575 0.1939061 0.3419379 0.2475233
[2,] 0.1939061 0.3204951 0.2303478 0.2022423
[3,] 0.3419379 0.2303478 0.5288435 0.2943051
[4,] 0.2475233 0.2022423 0.2943051 0.4599648
you can see, that the values are way too large, so where is my mistake?
Without actual data this is an unverifiable statement.
But you probably have to move the statement
summe2 <- 0
to inside the i-forloop just before the a-forloop.
summe2 <- 0
for(a in 1:100){
?
so that summe2 is initialized to 0 every time you use it as an accumulator in the a-forloop.
Furthermore there is no need to initialize dummy2. It gets overwritten continuously.
Berend
-- Neumann, Conrad