Looking for simpler solution to probabilistic question
Hi Dimitris that was EXACTLY what I was looking for Thanks Rainer
Dimitris Rizopoulos wrote:
matrix(age1, ncol=length(age1), nrow=length(age2), byrow=TRUE) + age2 can be replaced by outer(age2, age1, "+") and the same for 'p'. Best, Dimitris ---- Dimitris Rizopoulos Ph.D. Student Biostatistical Centre School of Public Health Catholic University of Leuven Address: Kapucijnenvoer 35, Leuven, Belgium Tel: +32/(0)16/336899 Fax: +32/(0)16/337015 Web: http://med.kuleuven.be/biostat/ http://www.student.kuleuven.be/~m0390867/dimitris.htm ----- Original Message ----- From: "Rainer M Krug" <R.M.Krug at gmail.com> To: "r-help" <r-help at stat.math.ethz.ch> Sent: Tuesday, January 15, 2008 1:24 PM Subject: [R] Looking for simpler solution to probabilistic question
Hi I have two processes which take with a certain probability (p1 and p2) x number of years to complete (age1 and age2). As soon as thge first process is completed, the second one begins. I want to calculate the time it takes for the both processes to be completed. I have the following script which gives me the answer, butI think there must be a more elegant way of doing the calculations between the ##### Any ideas welcom, Rainer age1 <- 1:20 p1 <- dnorm(age1,10,2) age2 <- 10:30 p2 <- dnorm(age2,15,1) ###### age <- matrix(age1, ncol=length(age1), nrow=length(age2), byrow=TRUE) + age2 p <- matrix(p1, ncol=length(p1), nrow=length(p2), byrow=TRUE) + p2 p <- as.numeric(tapply(p, age, sum)) p <- p / sum(p) ##### age <- sort(unique(as.numeric(age))) plot(age, p) lines(age1, p1) lines(age2, p2)
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