3D array was L(x,y,t)?
Hi Bill,
This is what I wound up doing to create a 3D array: I used outer to create a 2D array, and used a loop around outer to handle the third index. I guess R/S only has constructs for fast 2D array handling (e.g. outer). If you have higher dimensional arrays you apply outer() to 2D portions of them. I would appreciate any improvements over my solution.
Well your function does not appear to need outer at all. If you want to create a n-D array of function values over a grid in n variables and your function is simple, as yours appears to be, you can just use (for your example) grid <- expand.grid(x=seq(1, 66), y=seq(1, 31), time=seq(1, 19)) grid <- as.matrix(grid) z0 <- apply(grid, 1, function(v) f0(v[1], v[2], v[3])) (although this is not optimal!). Then just dim(z0) appropriately. However, your functions do appear to be a bit strange. Can it be right that y appears nowhere in the body of either f0 or f1?
corr.contrast3<-function(v0=.01, v1=-.01, phase=0)
{
#uses 3D rep of signals: s0(x,y,t)
#note corr=0 if v1=v0+pi/2 (orthogonal)
x<-seq(1,66)
y<-seq(1,31)
z0<-rep(0,66*31*19)
dim(z0)<-c(66,31,19)
z1<-z0
f0<-function(x,y,time) .45*cos(2*pi*3*x/66+v0*time)
f1<-function(x,y,time) .45*cos(2*pi*3*x/66+v1*time+phase)
for(time in seq(1,19))
{
z0[,,time]<-outer(x,y,f0,time)
z1[,,time]<-outer(x,y,f1,time)
}
energy<-sum(z0^2+z1^2)/2
corr<-sum(z0*z1)/energy
list(corr=corr,energy=energy)
}
Cheers, Jonathan. Jonathan Rougier Science Laboratories Department of Mathematical Sciences South Road University of Durham Durham DH1 3LE http://www.maths.dur.ac.uk/stats/people/jcr/jcr.html -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._