Help with Krippendorff's Alpha
Hi Jean, kripp.alpha expects a classifier by object (in your case, score) matrix as the first argument. If I read your code correctly you are getting the scores zigzagging across six columns when you want a 6 x 180 matrix. My guess is that you want: Trainers<-matrix(c(Trainer_1,Trainer_2, Trainer_3, Trainer_5, Trainer_6, Trainer_12), nrow=6,byrow=TRUE) Jim
On Sat, Jan 23, 2021 at 10:24 AM Jenn Russell <jenncami at hotmail.com> wrote:
Hello! I am requesting help for a data set in which I have 6 evaluators (I've called them 'Trainers'), each of which took a questionnaire with 180 questions. The possible answers to the questions are ordinal numbers. I am looking to test inter-rater reliability of the questionnaire using Krippendorff's alpha. I have already run this in R, however when I get the output it seems the matrix is inverted. While it seems like it should be an easy problem to fix I don't see how I would be able to create my matrix the other way without typing out all 180 scores manually. For reference, I'm using the irr package to use kripp.alpha().
Trainers<-matrix(c(Trainer_1,Trainer_2, Trainer_3, Trainer_5, Trainer_6, Trainer_12), ncol=6)
kripp.alpha(Trainers, method=c("ordinal"))
Krippendorff's alpha
Subjects = 6
Raters = 180
alpha = -0.00149
While I'm getting an output - shouldn't my raters be 6 and my subjects be 180?
Appreciate the help!
JR
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