How I can rearrange columns in data.frame?

arun

Mon, May 27, 2013 11:46 AM

Hi,
Try this:
dat2<-dat[order(as.numeric(gsub("preV(\\d+).*","\\1",colnames(dat))))]
?dat2
#? preV15A1b preV59A1b preV1001A1b preV2032A1b preV2035A1b
#1????? 0.57????? 0.05??????? 0.59??????? 0.40??????? 0.95
#2????? 0.62????? 0.57??????? 0.30??????? 0.80??????? 0.67
#3????? 0.51????? 0.03??????? 0.78??????? 0.24??????? 0.81
#4????? 0.95????? 0.50??????? 0.43??????? 0.34??????? 0.80


identical(dat1,dat2)
#[1] TRUE
A.K.


Hi R-User, 
I am wondering how I can rearrange columns in a table in R. I do 
have very big data set (4500 columns). I have given an example of the 
data set.

structure(list(preV1001A1b = c(0.59, 0.3, 0.78, 0.43), preV15A1b = c(0.57, 
0.62, 0.51, 0.95), preV2032A1b = c(0.4, 0.8, 0.24, 0.34), preV2035A1b = c(0.95, 
0.67, 0.81, 0.8), preV59A1b = c(0.05, 0.57, 0.03, 0.5)), .Names = c("preV1001A1b", 
"preV15A1b", "preV2032A1b", "preV2035A1b", "preV59A1b"), class = "data.frame", row.names = c(NA, 
-4L)) 

I wanted to make like this

structure(list(preV15A1b = c(0.57, 0.62, 0.51, 0.95), preV59A1b = c(0.05, 
0.57, 0.03, 0.5), preV1001A1b = c(0.59, 0.3, 0.78, 0.43), preV2032A1b = c(0.4, 
0.8, 0.24, 0.34), preV2035A1b = c(0.95, 0.67, 0.81, 0.8)), .Names = c("preV15A1b", 
"preV59A1b", "preV1001A1b", "preV2032A1b", "preV2035A1b"), class = "data.frame", row.names = c(NA, 
-4L)) 
Any suggestions. 
KG