a < b < c is alway TRUE

3 < 2

[1] FALSE

F < 1

[1] TRUE

as.numeric(F)

[1] 0


p.


On Fri, Jul 06, 2001 at 12:08:51PM +0200, Monika Ferster wrote:

Uwe Ligges writes:

 > One of our students did something like:
 > 
 >   x[a < b < c]
 > 
 > instead of 
 > 
 >   x[a < b & b < c]
 > 
 > 
 > But why is
 > 
 >   3 < 2 < 1	# [1] TRUE ???
 > 

3 < 2 < 1 seems to be seen like a double no because 3 < 2 < 1 < 0 returns
F. It looks like the multiplication of -1 what is strange, because F
corresponds to the value 0. So if you do (3<2)*(2<1) you get 0 and not the
value of T (=1).
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