create function for compare two dataframe.
Hello Petr I'll send mail with plain text format at next time. (I didn't know how to send plain text mail on gmail) Thanks. 2016?3?1?(?) 16:07 PIKAL Petr <petr.pikal at precheza.cz>:
Hi You said When I asked this question, I used indent for readability. So maybe it was added extra space. I executed same command. It has no extra space.
str(s1)
'data.frame': 3 obs. of 4 variables: $ ID : Factor w/ 3 levels "ID1","ID2","ID3": 1 2 3 $ VAL1: int 2 0 0 $ VAL2: int 2 3 2 $ VAL3: int 3 3 4
str(s2)
'data.frame': 3 obs. of 4 variables: $ ID : Factor w/ 3 levels "ID1","ID2","ID3": 1 2 3 $ VAL1: int 0 0 0 $ VAL2: int 2 2 2 $ VAL3: int 3 3 2 That is why dput(s1) is always preferable for exchanging data instead of text in ***HTML formated*** mail. Cheers Petr *From:* Hiroyuki Sato [mailto:hiroysato at gmail.com] *Sent:* Monday, February 29, 2016 12:04 PM *To:* PIKAL Petr; r-help at r-project.org *Subject:* Re: [R] create function for compare two dataframe. Hello Petr. Thank you for replying. Your step is better than my step!. I added one step
s.dcast <- dcast(s.m, ID+variable~dat)
subset(s.dcast,df1!=df2)
ID variable df1 df2 1 ID1 VAL1 2 0 5 ID2 VAL2 3 2 9 ID3 VAL3 4 2 This output is what I wanted!!. P.S. When I asked this question, I used indent for readability. So maybe it was added extra space. I executed same command. It has no extra space.
str(s1)
'data.frame': 3 obs. of 4 variables: $ ID : Factor w/ 3 levels "ID1","ID2","ID3": 1 2 3 $ VAL1: int 2 0 0 $ VAL2: int 2 3 2 $ VAL3: int 3 3 4
str(s2)
'data.frame': 3 obs. of 4 variables: $ ID : Factor w/ 3 levels "ID1","ID2","ID3": 1 2 3 $ VAL1: int 0 0 0 $ VAL2: int 2 2 2 $ VAL3: int 3 3 2 Best regards. 2016?2?29?(?) 18:16 PIKAL Petr <petr.pikal at precheza.cz>: Hi You does not need to create function, you can use functions already available.
s1<- read.table("clipboard", header=T, sep=",")
s2<- read.table("clipboard", sep=",")
You presented second table without names.
names(s2) <- names(s1)
s1
ID VAL1 VAL2 VAL3 1 ID1 2 2 3 2 ID2 0 3 3 3 ID3 0 2 4
s2
ID VAL1 VAL2 VAL3 1 ID1 0 2 3 2 ID2 0 2 3 3 ID3 0 2 2 You need to add a column in which you specify data frame and merge them
s1$dat<-"df1" s2$dat<-"df2" s<-merge(s1,s2, all=T)
Now you need to reshape your data
library(reshape2)
s.m<-melt(s)
Using ID, dat as id variables
s.m
ID dat variable value 1 ID1 df1 VAL1 2 2 ID2 df2 VAL1 0 3 ID2 df1 VAL1 0 4 ID3 df2 VAL1 0 5 ID3 df1 VAL1 0 6 ID1 df2 VAL1 0 7 ID1 df1 VAL2 2 8 ID2 df2 VAL2 2 9 ID2 df1 VAL2 3 10 ID3 df2 VAL2 2 11 ID3 df1 VAL2 2 12 ID1 df2 VAL2 2 13 ID1 df1 VAL3 3 14 ID2 df2 VAL3 3 15 ID2 df1 VAL3 3 16 ID3 df2 VAL3 2 17 ID3 df1 VAL3 4 18 ID1 df2 VAL3 3 And cast the new structure.
dcast(s.m, ID+variable~dat)
ID variable df1 df2 1 ID1 VAL1 2 NA 2 ID1 VAL2 2 NA 3 ID1 VAL3 3 NA 4 ID2 VAL1 0 0 5 ID2 VAL2 3 2 6 ID2 VAL3 3 3 7 ID3 VAL1 0 0 8 ID3 VAL2 2 2 9 ID3 VAL3 4 2 10 ID1 VAL1 NA 0 11 ID1 VAL2 NA 2 12 ID1 VAL3 NA 3 This was the point that I was rather surprised but I found a reason. Your ID variable does not have 3 but four values - although ID1 looks the same, in one there is an extra space, therefore you have different ID1 in s1 from ID1 in s2. That is why it is recommended to use dput() for exchanging data with others.
str(s)
'data.frame': 6 obs. of 5 variables: $ ID : Factor w/ 4 levels " ID1"," ID2",..: 1 2 2 3 3 4 $ VAL1: int 2 0 0 0 0 0 $ VAL2: int 2 2 3 2 2 2 $ VAL3: int 3 3 3 2 4 3 $ dat : chr "df1" "df2" "df1" "df2" ...
s1$ID
[1] ID1 ID2 ID3 Levels: ID1 ID2 ID3
s2$ID
[1] ID1 ID2 ID3 Levels: ID2 ID3 ID1
str(s1)
'data.frame': 3 obs. of 5 variables: $ ID : Factor w/ 3 levels " ID1"," ID2",..: 1 2 3 $ VAL1: int 2 0 0 $ VAL2: int 2 3 2 $ VAL3: int 3 3 4 $ dat : chr "df1" "df1" "df1"
str(s2)
'data.frame': 3 obs. of 5 variables: $ ID : Factor w/ 3 levels " ID2"," ID3",..: 3 1 2 $ VAL1: int 0 0 0 $ VAL2: int 2 2 2 $ VAL3: int 3 3 2 $ dat : chr "df2" "df2" "df2"
Cheers Petr
-----Original Message-----
From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of
Hiroyuki Sato
Sent: Monday, February 29, 2016 9:44 AM
To: r-help at r-project.org
Subject: [R] create function for compare two dataframe.
Hello
I would like to create a funciton which is create new dataframe for
compare reslut of two dataframes.
No. COLUMN DF1 DF2
"1" "VAL1" "2" "0" # <- compare ID1,VAL1
"2" "VAL2" "3" "2" # <- comapre ID2,VAL2
"3" "VAL3" "4" "2" # <- compare ID3,VAL3
s1 <- read.table("sample1.txt",header=T,sep=',')
s2 <- read.table("sample2.txt",header=T,sep=',')
comp_data(df1,df2)
sample1.txt
ID,VAL1,VAL2,VAL3
ID1,2,2,3
ID2,0,3,3
ID3,0,2,4
sample2.txt
ID1,0,2,3
ID2,0,2,3
ID3,0,2,2
I created the functions, but I got the following error.
Could you tell me how to add new frame data?
Or alternative way?
1: In `[<-.factor`(`*tmp*`, ri, value = "3") :
invalid factor level, NA generated
2: In `[<-.factor`(`*tmp*`, ri, value = "VAL3") :
invalid factor level, NA generated
3: In `[<-.factor`(`*tmp*`, ri, value = "4") :
invalid factor level, NA generated
comp_data <- function(df1,df2) {
#
# create null data.frame
out <- data.frame(matrix(rep(NA,4),nrow=1))[numeric(0), ]
colnames(out) <- c("ID","Site","df1","df2")
# column names
col_names <- colnames(df1)
# col_size
col_size <- ncol(df1)
row_size <- nrow(df1)
for( col in 2:col_size ){
for( row in 1:row_size ){
if( df1[row,col] != df2[row,col] ){
out <-
rbind(out,c(df1[row,1],col_names[col],df1[row,col],df2[row,col]))
}
}
}
out
}
Best regards.
[[alternative HTML version deleted]]
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