Data manipulation in a data.frame

Hi IOanna,

Do you have rows with multiple '1's?? If not, you could also try:
A$Variable <- c("none",names(A)[-1])[1+with(A,B+2*C+3*D)]
A.K.

Thank you very much. One further question. 

Assuming that for some points there is no classification for example:

A<-data.frame(A=c(10,100,1000,30,50,60,300,3),

? ? ? ? ? ? ? B=c(0,1,1,1,0,0,0,0),? ? ? ? ? ? ? ? ? ? ? ? 

? ? ? ? ? ? ? C=c(0,0,0,0,1,1,0,0),

? ? ? ? ? ? ? D=c(1,0,0,0,0,0,1,0))

Is there an easy way to introduce an extra none option in the variable?

A<-data.frame(A=c(10,100,1000,30,50,60,300,3),

? ? ? ? ? ? ? B=c(0,1,1,1,0,0,0,0),? ? ? ? ? ? ? ? ? ? ? ? 

? ? ? ? ? ? ? C=c(0,0,0,0,1,1,0,0),

? ? ? ? ? ? ? D=c(1,0,0,0,0,0,1,0),

? ? ?  Variable=c(D,B,B,B,C,C,D,none))

Thanks in advance, 
IOanna


-----Original Message-----
From: arun [mailto:smartpink111 at yahoo.com] 
Sent: 21 February 2014 00:19
To: r-help at r-project.org
Cc: ioanna ioannou
Subject: Re: [R] Data manipulation in a data.frame

Also,
rownames(which(t(!!A[,-1]),arr.ind=TRUE))
A.K.

Hi,
May be this helps:

A$Variable <- rep(colnames(A[,-1]),nrow(A))[t(!!A[,-1])]
A.K.



On Thursday, February 20, 2014 5:55 PM, ioanna ioannou <ii54250 at msn.com>
wrote:
Hello,





Assuming that I have a data frame 

A<-data.frame(A=c(10,100,1000,30,50,60,300),

? ? ? ? ? ? ? B=c(0,1,1,1,0,0,0),? ? ? ? ? ? ? ? ? ? ? ? 

? ? ? ? ? ? ? C=c(0,0,0,0,1,1,0),

? ? ? ? ? ? ? D=c(1,0,0,0,0,0,1))



What I would like is to introduce a new column Variable such that:



A<-data.frame(A=c(10,100,1000,30,50,60,300),

? ? ? ? ? ? ? B=c(0,1,1,1,0,0,0),? ? ? ? ? ? ? ? ? ? ? ? 

? ? ? ? ? ? ? C=c(0,0,0,0,1,1,0),

? ? ? ? ? ? ? D=c(1,0,0,0,0,0,1),

? ? ?? Variable=c(D,B,B,B,C,C,D)) 



How can I do it?



Best 

IOanna


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