generating a sequence of seconds
On Aug 12, 2014, at 2:49 PM, John McKown <john.archie.mckown at gmail.com> wrote:
And some people wonder why I absolutely abhor daylight saving time. I'm not really fond of leap years and leap seconds either. Somebody needs to fix the Earth's rotation and orbit!
I have been a longtime proponent of slowing the rotation of the Earth on its axis, so that we could have longer days to be more productive. Unfortunately, so far, my wish has gone unfulfilled...at least as it is relevant within human lifetimes. ;-) Regards, Marc
On Tue, Aug 12, 2014 at 2:14 PM, William Dunlap <wdunlap at tibco.com> wrote:
What if I just want the seconds vector without the date, please? Is there a convenient way to create such a vector, please?
Why do you want such a thing? E.g., do you want it to print the time of day without the date? Or are you trying to avoid numeric problems when you do regressions with the seconds-since-1970 numbers around 1414918800? Or is there another problem you want solved? Note that the number of seconds in a day depends on the day and the time zone. In US/Pacific time I get:
length(seq(from=as.POSIXct("2014-08-12
00:00:00"),to=as.POSIXct("2014-08-12 23:59:59"), by="secs"))
[1] 86400
length(seq(from=as.POSIXct("2014-03-09
00:00:00"),to=as.POSIXct("2014-03-09 23:59:59"), by="secs"))
[1] 82800
length(seq(from=as.POSIXct("2014-11-02
00:00:00"),to=as.POSIXct("2014-11-02 23:59:59"), by="secs"))
[1] 90000
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, Aug 12, 2014 at 11:51 AM, Erin Hodgess <erinm.hodgess at gmail.com> wrote:
Hello! If I would like to generate a sequence of seconds for a date, I would do the following: x <- seq(from=as.POSIXct(2014-08-12 00:00:00),to=as.POSIXct(2014-08-12 23:59:59),by="secs") What if I just want the seconds vector without the date, please? Is there a convenient way to create such a vector, please? thanks, Erin