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Is = now the same as <- in assigning values

Wacek Kusnierczyk
Kenn Konstabel wrote:
if you think the use of force guarantees that x is assigned 43, you're
wrong.

foo = function(a) 0
x = 1
foo(a=force(x=2))
x

foo = function(a) deparse(substitute(a))
x = 1
foo(a=force(x=2))
x

in both cases, the result (the final value of x, but not the value
returned by foo in the second example) does not change when you replace
'force(x=2)' with 'x<-2'.

vQ

Thread (17 messages)

Petter Hedberg Is = now the same as <- in assigning values Dec 15 Jorge Ivan Velez Is = now the same as <- in assigning values Dec 15 Gabor Grothendieck Is = now the same as <- in assigning values Dec 15 Wacek Kusnierczyk Is = now the same as <- in assigning values Dec 15 Wacek Kusnierczyk Is = now the same as <- in assigning values Dec 15 Petter Hedberg Is = now the same as <- in assigning values Dec 16 Kenn Konstabel Is = now the same as <- in assigning values Dec 18 Peter Dalgaard Is = now the same as <- in assigning values Dec 18 Duncan Murdoch Is = now the same as <- in assigning values Dec 18 Kenn Konstabel Is = now the same as <- in assigning values Dec 18 Wacek Kusnierczyk Is = now the same as <- in assigning values Dec 18 Wacek Kusnierczyk Is = now the same as <- in assigning values Dec 18 Wacek Kusnierczyk Is = now the same as <- in assigning values Dec 18 Stavros Macrakis Is = now the same as <- in assigning values Dec 18 Wacek Kusnierczyk Is = now the same as <- in assigning values Dec 18 Peter Dalgaard Is = now the same as <- in assigning values Dec 18 Wacek Kusnierczyk Is = now the same as <- in assigning values Dec 18