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lm() with same formula but different column/factor combinations in data frame

Try variations of this:

library(leaps)
b<-regsubsets(Fertility~.,data=swiss)
w <- summary(b)$which
lapply(1:nrow(w), function(i) coef(lm(Fertility ~., swiss[w[i, ]])))
On Fri, Dec 26, 2008 at 1:57 PM, Murtaza Das <murtazadas at gmail.com> wrote: