Continuous variable into levels
Thank you dear Rui Yes, it helps. Best regards
On Thursday, March 3, 2022, Rui Barradas <ruipbarradas at sapo.pt> wrote:
Hello, And ?findInterval is faster than hist. findInterval(x, c(-Inf, 500, 1000, 5000)) Also, before the cut code, the OP wrote if value is between 1-100 do something but in the breaks vector there's no 100. I guess this is not important, though, only the function to bin the data is. Hope this helps, Rui Barradas ?s 22:38 de 03/03/2022, Jim Lemon escreveu:
Sorry, it was such an easy question that I didn't even read it closely. Apparently using hist() is a bit faster. Whether this is worth it, I don't know. Jim On Fri, Mar 4, 2022 at 9:36 AM Neha gupta <neha.bologna90 at gmail.com> wrote:
Hello Jim So, you believe the following way is better ? var2=cut(var1, br=c(-1,500, 501,1000, 1001,5000)) On Thu, Mar 3, 2022 at 11:29 PM Jim Lemon <drjimlemon at gmail.com> wrote:
Hi Neha, I think you're looking for the "cut" function. Jim On Fri, Mar 4, 2022 at 8:10 AM Neha gupta <neha.bologna90 at gmail.com> wrote:
Hello everyone
I have a variable with about 5000 different values
var1= c(0, 123, 400, .....4988)
I want to convert it into different levels for some comparisons like
if value is between 1-100 do something
else
do other things
Is there any sophisticated way to do that than the following:
var2=cut(var1, br=c(-1,500, 501,1000, 1001,5000))
Thank you
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______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posti ng-guide.html and provide commented, minimal, self-contained, reproducible code.