Using the output of strsplit

Tena koe Jim

You could use unlist and matrix.  For example:
tempList
[[1]]
[1] "a" "A"

[[2]]
[1] "b" "B"

[[3]]
[1] "c" "C"
unlist(tempList)
[1] "a" "A" "b" "B" "c" "C"
matrix(unlist(tempList), nrow=3)
[,1] [,2]
[1,] "a"  "B" 
[2,] "A"  "c" 
[3,] "b"  "C"
matrix(unlist(tempList), nrow=3, byrow=T)
[,1] [,2]
[1,] "a"  "A" 
[2,] "b"  "B" 
[3,] "c"  "C"
matrix(unlist(tempList), nrow=3, byrow=T)[,1]
[1] "a" "b" "c"

HTH ....

Peter Alspach
-----Original Message-----
From: r-help-bounces at r-project.org 
[mailto:r-help-bounces at r-project.org] On Behalf Of James Rome
Sent: Tuesday, 19 January 2010 10:49 a.m.
To: r-help at r-project.org
Subject: [R] Using the output of strsplit

I successfully combined my data frames, and am now on my next hurdle.

I had combined the data and quarter, and used tapply to count 
the entries for each unique date/quarter pair.
ar= tapply(ewrgnd$gw, list(ewrgnd$dq), sum)   #for each date/quarter
combination sums the gw (which are all 1)
dq=row.names(ar)
spl=strsplit(dq)
But I need to split them back into the separate date and 
quarter. So I used strsplit(), and get
spl
[[1]]
[1] "2009-01-01" "60"       

[[2]]
[1] "2009-01-01" "61"       

[[3]]
[1] "2009-01-01" "62"       

[[4]]
[1] "2009-01-01" "63"       

[[5]]
[1] "2009-01-01" "68"       
. . .

But lists throw me. I want to get separate vectors of the 
date and quarter out of my list. All the things I have seen 
extract rows from the list. I need to extract columns.

Thanks list,
Jim Rome

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Using the output of strsplit

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