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HI

on 09/16/2008 09:20 AM Richard.Cotton at hsl.gov.uk wrote:
The correct syntax using is.na() would be:
a b
1 1 1
2 2 0
3 3 0
4 0 1
5 3 1
6 4 0
7 0 1
8 5 1
9 2 0


is.na(df) <- df == 0
a  b
1  1  1
2  2 NA
3  3 NA
4 NA  1
5  3  1
6  4 NA
7 NA  1
8  5  1
9  2 NA


Review ?is.na for correct use.

HTH,

Marc Schwartz