What is an alternative to expand.grid if create a long vector?
Hi Keep your mails on the list. Actually you did not say much about your data and the way how do you want to model them. There are plenty of modelling functions in R starting with e.g. lm but I am not aware of a procedure in which you just design your explanatory variables to set plausible model. But I am not expert in statistics and this list is not ment for solving statistical problems. Cheers Petr From: Shah Alam <dr.alamsolangi at gmail.com> Sent: Monday, April 19, 2021 5:20 PM To: PIKAL Petr <petr.pikal at precheza.cz> Subject: Re: [R] What is an alternative to expand.grid if create a long vector? Dear Petr, Thanks for your response. I am designing a model with 10 unknown parameters. generating the combination of unknown parameters will be used in the model to estimate the set of vectors that fits well to actual data. Is there any other was to do it? I also used randomLHS function from lhs package. But, it did not serve the purpose. Best regards, Shah Alam On Mon, 19 Apr 2021 at 16:07, PIKAL Petr <petr.pikal at precheza.cz
<mailto:petr.pikal at precheza.cz> > wrote:
Hi Actually expand.grid produces data frame and not vector. And dimension of the data frame is "big"
dim(A)
[1] 100000000 4
str(A)
'data.frame': 100000000 obs. of 4 variables: $ Var1: num 0.001 0.002 0.003 0.004 0.005 0.006 0.007 0.008 0.009 0.01 ... $ Var2: num 1e-04 1e-04 1e-04 1e-04 1e-04 1e-04 1e-04 1e-04 1e-04 1e-04 ... $ Var3: num 0.38 0.38 0.38 0.38 0.38 0.38 0.38 0.38 0.38 0.38 ... $ Var4: num 0.12 0.12 0.12 0.12 0.12 0.12 0.12 0.12 0.12 0.12 ... - attr(*, "out.attrs")=List of 2 ..$ dim : int [1:4] 100 100 100 100 ..$ dimnames:List of 4 .. ..$ Var1: chr [1:100] "Var1=0.001" "Var1=0.002" "Var1=0.003" "Var1=0.004" ... .. ..$ Var2: chr [1:100] "Var2=0.0001000000" "Var2=0.0001090909" "Var2=0.0001181818" "Var2=0.0001272727" ... .. ..$ Var3: chr [1:100] "Var3=0.3800000" "Var3=0.3804040" "Var3=0.3808081" "Var3=0.3812121" ... .. ..$ Var4: chr [1:100] "Var4=0.1200000" "Var4=0.1206061" "Var4=0.1212121" "Var4=0.1218182" ...
in case of 4 sequences 1e8 rows, 4 columns in case of 10 sequences 1e20 rows and 10 columns in your last example 1.4e8 rows and 10 columns which probably cross the memory capacity of your PC. Maybe you could increase memory of you PC. If I am correct to store the first you need about 3.2GB, to strore the last 11.2 GB. May I ask what you want to do with such a big object? Cheers Petr
-----Original Message----- From: R-help <r-help-bounces at r-project.org <mailto:r-help-bounces at r-project.org> > On Behalf Of Shah Alam Sent: Monday, April 19, 2021 2:36 PM To: r-help mailing list <r-help at r-project.org <mailto:r-help at r-project.org>
>
Subject: [R] What is an alternative to expand.grid if create a long
vector?
Dear All, I would like to know that is there any problem in *expand.grid* function
or it
is a limitation of this function. I am trying to create a combination of elements using expand.grid
function.
A <- expand.grid( c(seq(0.001, 0.1, length.out = 100)), c(seq(0.0001, 0.001, length.out = 100)), c(seq(0.38, 0.42, length.out =
100)),
c(seq(0.12, 0.18, length.out = 100))) Four combinations work fine. However, If I increase the combinations up to ten. The following error appears. A <- expand.grid( c(seq(0.001, 1, length.out = 100)), c(seq(0.0001, 0.001, length.out = 100)), c(seq(0.38, 0.42, length.out =
100)),
c(seq(0.12, 0.18, length.out = 100)), c(seq(0.01, 0.04, length.out =
100)),
c(seq(0.0001, 0.001, length.out = 100)), c(seq(0.0001, 0.001, length.out = 100)), c(seq(0.001, 0.01, length.out = 100)), c(seq(0.01, 0.3, length.out
= 100))
) *Error in rep.int <http://rep.int> <http://rep.int>(rep.int <http://rep.int> <http://rep.int>(seq_len(nx), rep.int <http://rep.int> <http://rep.int>(rep.fac, nx)), orep) : invalid 'times' value* After reducing the length to 10. It produced a different type of error A <- expand.grid( c(seq(0.001, 0.005, length.out = 10)), c(seq(0.0001, 0.0005, length.out = 10)), c(seq(0.38, 0.42, length.out =
5)),
c(seq(0.12, 0.18, length.out = 7)), c(seq(0.01, 0.04, length.out = 5)), c(seq(0.0001, 0.001, length.out = 10)), c(seq(0.0001, 0.001, length.out =
10)),
c(seq(0.001, 0.01, length.out = 10)), c(seq(0.1, 0.8, length.out = 8))
)
*Error: cannot allocate vector of size 1.0 Gb*
What is an alternative to expand.grid if create a long vector based on 10
elements?
With kind regards,
Shah Alam
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