BY GROUP IN GEV
HI:
Since you didn't provide a reproducible example (in particular, what
does str(MA) return?), it's hard to verify what specifically causes
the error, but a look at the gev() function's help page indicates that
the first argument is supposed to be a (numeric) vector, apparently
atomic.
One problem with this code,
CP <- lapply(MAS, function(x){gev(MAS$CP1, 100, method = "BFGS", control =
list(maxit = 500))})
is that there is no 'x' in the body of the function. Perhaps you need
to generate a numeric vector for CP1 before feeding it to gev(), but
without a reproducible example this is nothing more than speculation.
Perhaps something like:
CP <- lapply(MAS, function(x){
y <- as.numeric(x$CP1)
gev(y, 100, method = "BFGS", control = list(maxit = 500))
})
Obviously untested for the reason stated above. A perusal of the
Posting Guide might be beneficial.
Dennis
On Mon, Jun 27, 2011 at 3:19 PM, Peter Maclean <pmaclean2011 at yahoo.com> wrote:
Hi Dennis:
I tried your suggestions and I am getting the following errors:
Error in x$CP1 : $ operator is invalid for atomic vectors
In addition: Warning message:
In sqrt(diag(varcov)) : NaNs produced
?Peter Maclean
Department of Economics
UDSM
----- Original Message ----
From: Dennis Murphy <djmuser at gmail.com>
To: Peter Maclean <pmaclean2011 at yahoo.com>
Sent: Wed, June 22, 2011 11:37:02 PM
Subject: Re: [R] BY GROUP IN GEV
Hi:
I think you need
CP ?<- lapply(MAS, function(x){gev(x$CP1, 100, method = "BFGS", control =
? ? ? ? ? ? ? ? ? ? list(maxit = 500))})
See if that works out.
HTH,
Dennis
On Wed, Jun 22, 2011 at 4:06 PM, Peter Maclean <pmaclean2011 at yahoo.com> wrote:
I am trying to run gev (general extreme value) function in ?evir? package. My data is divided by state. I am using the following codes but it is not
working.
I will appreciate any help.
#Split data
MAS <- split(MA, MA$states)
CP ?<- lapply(MAS, function(x){gev(MAS$CP1, 100, method = "BFGS", control =
list(maxit = 500))})
the Error message is:
Error in tapply(data, grouping, max) : arguments must have same length
I know there are also ?by? function,? but I could not figure it out how to use
it.
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