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Improvement: function cut

Hello Andrew,


I add this info as a completion (so other users can get a better 
understanding):

If we want to perform a survival analysis, than the interval should be 
closed to the right, but we should include also the first time point (as 
per Intention-to-Treat):

[0, 4](4, 8](8, 12](12, 16]

[0, 4](4, 8](8, 12](12, 16](16, 20]


So the series is extendible to the right without any errors!

But the 1st interval (which is the same in both series) is different 
from the other intervals: [0, 4].


I feel that this should have been the default behaviour for cut().

Note:

I was induced to think about a different situation in my previous 
message, as you constructed open intervals on the right, and also 
extended to the right. But survival analysis should be as described in 
this mail and should probably be the default.


Sincerely,


Leonard
On 9/18/2021 1:29 AM, Andrew Simmons wrote: