how to rename variables by lopping off first 3 characters

read.table(text="Temp (\u{b0}C)\tLength (cm)\n37.8\t145\n", sep="\t",

read.table(text="Temp (\u{b0}C)\tLength (cm)\n37.8\t145\n", sep="\t",

Hello,

I have already seen those names starting with 'i..' several times but I
don't remember where nor why.
I think it has to do with encoding. Or maybe special characters. I have
the impression that the best solution was to read the data in a way as
to avoid the problem.

Using Bert's example data set, here are base R and tidyverse solutions.


dat <- data.frame(
   i..One = 1:3,
   i..Two = letters[1:3],
   ixx = 5:7)

# base R
names(dat) <- sub("^i\\.\\.", "", names(dat))
names(dat)

# tidyverse
dplyr::rename_with(dat, .fn = \(x) sub("^i\\.\\.", "", x),
starts_with("i.."))


Hope this helps,

Rui Barradas

?s 16:26 de 14/03/2022, Christopher W Ryan via R-help escreveu:

I have data coming to me from another source, in which some of the

variable

names begin with "i.."

As in "i..actual_meaningful_var_name"

I would like to remove the first three characters from any variable name

if

they are "i.."

I'm using R on Win 10 and dplyr, so ideally I'm looking for a dplyr
solution. Apparently I'm just not understanding how the various select,
contains, rename_at, rename_with, and so-on dplyr expressions work. I've
tried various arrangements of them, usually resulting in

Error: `contains()` must be used within a *selecting* function.
i See <https://tidyselect.r-lib.org/reference/faq-selection-context.html


A simple select(contains(foo)) I can do fine, to select a subset of
variables. It's combining it with renaming that I am struggling with.

Grateful for any advice.

Thanks.

--Chris Ryan

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