colmeans not working

Dear Arun,
on having a bird eye view i came to notice that the data you are using dont have month column at the beginning.
my initial data was
> res

$EE
? ?month ? ? ?2005 ? ? ?2006 ? ? ?2008 ? ? ?2009
1 ? ? ?1 1.7360776 0.8095275 1.6369044 0.8195241
2 ? ? ?2 0.6962079 3.8510720 0.4319758 2.3304495
3 ? ? ?3 1.0423625 2.7687266 0.2904245 0.7015527
4 ? ? ?4 2.4158326 1.2315324 1.4287387 1.5701019

$WW
? ?month ? ? ? 2008 ? ? ?2009 ? ? ?2010
1 ? ? ?1 ?1.4737028 ?2.314878 ?2.672661
2 ? ? ?2 ?1.6700918 ?2.609722 ?2.112421
3 ? ? ?3 ?3.2387775 ?7.305766 ?6.939536
4 ? ? ?4 ?6.7063592 18.745256 13.278218
afterwards i used eliminated the month column and got

$EE
? ? ? ? 2005 ? ? ?2006 ? ? ?2008 ? ? ?2009
1 ?1.7360776 0.8095275 1.6369044 0.8195241
2 ?0.6962079 3.8510720 0.4319758 2.3304495
3 ?1.0423625 2.7687266 0.2904245 0.7015527
4 ?2.4158326 1.2315324 1.4287387 1.5701019

$WW
? ? ? ? ?2008 ? ? ?2009 ? ? ?2010
1 ? 1.4737028 ?2.314878 ?2.672661
2 ? 1.6700918 ?2.609722 ?2.112421
3 ? 3.2387775 ?7.305766 ?6.939536
4 ? 6.7063592 18.745256 13.278218

now when i m aPPLYING rowMeans or colMeans, i am getting error.
i m attaching the text file for better understandging


eliza

> Date: Sun, 23 Dec 2012 17:40:15 -0800
> From: smartpink111 at yahoo.com
> Subject: Re: [R] colmeans not working
> To: eliza_botto at hotmail.com
> CC: r-help at r-project.org; bbolker at gmail.com
> 
> Hi Eliza,
> 
> I tried with the example you gave.? Couldn't reproduce the error.? 
> 
> 
> res1<-list(read.table(text=" 
> ??????? 2005????? 2006????? 2008????? 2009 
> ? 1.7360776 0.8095275 1.6369044 0.8195241 
> ? 0.6962079 3.8510720 0.4319758 2.3304495 
> ? 1.0423625 2.7687266 0.2904245 0.7015527 
> ? 2.4158326 1.2315324 1.4287387 1.5701019 
> ",sep="",header=TRUE),read.table(text=" 
> ???????? 2008????? 2009????? 2010 
> ?? 1.4737028? 2.314878? 2.672661 
> ?? 1.6700918? 2.609722? 2.112421 
> ?? 3.2387775? 7.305766? 6.939536 
> ?? 6.7063592 18.745256 13.278218 
> ",sep="",header=TRUE))
> ?names(res1)<-c("EE","WW")
> res1<-lapply(res1,function(x) {names(x)<-gsub("X","",names(x));x})
> res1
> #$EE
> #?????? 2005????? 2006????? 2008????? 2009
> #1 1.7360776 0.8095275 1.6369044 0.8195241
> #2 0.6962079 3.8510720 0.4319758 2.3304495
> #3 1.0423625 2.7687266 0.2904245 0.7015527
> #4 2.4158326 1.2315324 1.4287387 1.5701019
> #
> #$WW
> #????? 2008????? 2009????? 2010
> #1 1.473703? 2.314878? 2.672661
> #2 1.670092? 2.609722? 2.112421
> #3 3.238777? 7.305766? 6.939536
> #4 6.706359 18.745256 13.278218
> lapply(res1,colMeans)
> #$EE
> #???? 2005????? 2006????? 2008????? 2009 
> #1.4726202 2.1652146 0.9470108 1.3554070 
> #
> #$WW
> #??? 2008???? 2009???? 2010 
> #3.272233 7.743906 6.250709 
> 
> ?lapply(res1,rowMeans)
> #$EE
> #[1] 1.250508 1.827426 1.200767 1.661551
> #
> #$WW
> #[1]? 2.153747? 2.130745? 5.828026 12.909944
> 
> 
> A.K.
> 
> 
> 
> ----- Original Message -----
> From: eliza botto <eliza_botto at hotmail.com>
> To: bbolker at gmail.com; r-help at stat.math.ethz.ch
> Cc: 
> Sent: Sunday, December 23, 2012 7:48 PM
> Subject: Re: [R] colmeans not working
> 
> 
> Dear Ben,Thanks for replying but its still not working.your code was>lapply(res,colMeans)but i want to use "res1" instead of "res". when i did use it, i got same error.eliza
> > To: r-help at stat.math.ethz.ch
> > From: bbolker at gmail.com
> > Date: Mon, 24 Dec 2012 00:31:41 +0000
> > Subject: Re: [R] colmeans not working
> > 
> > eliza botto <eliza_botto <at> hotmail.com> writes:
> > 
> > >? Dear useRs,You must all the planning for the christmas, but i am
> > > stucked in my office on the following issue i had a file containg
> > > information about station name, year, month, day, and discharge
> > > information. i opened it by using following command
> > 
> > > > dat1<-read.table("EL.csv",header=TRUE, sep=",",na.strings="NA")
> > 
> > You can probably use 
> > 
> > dat1 <- read.csv("EL.csv") 
> > 
> >???(although you may have to double-check some of the other
> > default differences between read.csv and read.table, e.g.
> > quote and comment.char arguments)
> > 
> > > then by using following codes suggested by arun and rui i managed to obtain an
> > output
> > 
> > library(reshape2)
> > res <- lapply(split(dat1,dat1$st),
> >? ? function(x) dcast(x,month~year,mean,value.var="discharge"))
> > 
> > [snip]
> >? 
> > res1 <- lapply(res, function(x)x[,-1])
> > 
> >???(c() is redundant here)
> > 
> > > $EE
> > >? ? ? ???2005? ? ? 2006? ? ? 2008? ? ? 2009
> > > 1? 1.7360776 0.8095275 1.6369044 0.8195241
> > > 2? 0.6962079 3.8510720 0.4319758 2.3304495
> > > 3? 1.0423625 2.7687266 0.2904245 0.7015527
> > > 4? 2.4158326 1.2315324 1.4287387 1.5701019
> > > 
> > > $WW
> > >? ? ? ? ? 2008? ? ? 2009? ? ? 2010
> > > 1???1.4737028? 2.314878? 2.672661
> > > 2???1.6700918? 2.609722? 2.112421
> > > 3???3.2387775? 7.305766? 6.939536
> > > 4???6.7063592 18.745256 13.278218
> > > 
> > > 
> > 
> > Now you just need
> > 
> > lapply(res,colMeans)
> > 
> > ______________________________________________
> > R-help at r-project.org mailing list
> > https://stat.ethz.ch/mailman/listinfo/r-help
> > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> > and provide commented, minimal, self-contained, reproducible code.
> ??? ???????? ?????? ??? ? 
> ??? [[alternative HTML version deleted]]
> 
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>