Simple question on eval

Here are two options that might work for you given the little bit you've said:

## If its the same parameter all 30 times
## say, for example, base = 4.5 to log
for(i in 1:30) {
  print(log(1:10, base = 4.5))
}

## if they are different parameters, you could try
lapply(X = c(1.3, 3, 2.2, 4, 5), FUN = function(x) {
  log(1:10, base = x)})

## the 'X' argument to lapply() is based, one at a time,
## to whatever the function is (the 'FUN' argument)
## so the above is equivalent to
log(1:10, base = 1.3)
log(1:10, base = 3)
log(1:10, base = 2.2)
log(1:10, base = 4)
log(1:10, base = 5)
## but easier to type

Cheers,

Josh

@Ivan do.call() passes a list of arguments, but I am not sure it would
easily adapt to passing 30 different arguments one at a time or even
the same argument 30 times.

Thank you so much Joshua. ?That's exactly what I am looking for.

What I wanted to do is to pass a parameter to a function and I have to run
the functions 30 times. ?Instead of typing them all out, I created a long
string of "f(a);f(b);f(c) ..." using paste() and use eval and parse to
evaluative them all at once. ?I am sure there are better ways of doing it
but I just know this.
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Joshua Wiley
Ph.D. Student, Health Psychology
University of California, Los Angeles
http://www.joshuawiley.com/