making a dataframe out of lapply() result
tester <- data.frame(groups=c("A","A","B","B","C","C"),
one=c(1,1,2,2,3,3), two=c(6,6,7,7,8,8))
> tester.L <- split(tester, tester$groups)
> as.data.frame(lapply(tester.L, function(x) x <- unlist(x[1,] )))
A B C
groups 1 2 3
one 1 2 3
two 6 7 8
How's this?
Spencer Graves
Remko Duursma wrote:
Dear R-helpers,
i have a question on how to vectorize this problem:
i have a dataframe:
tester <- data.frame(groups=c("A","A","B","B","C","C"), one=c(1,1,2,2,3,3), two=c(6,6,7,7,8,8))
# i split it into a list
tester.L <- split(tester, tester$groups)
# And want to keep only the first item in each:
lapply(tester.L, function(x) x <- x[1,] )
How do i make a dataframe out of the last result, which looks like "tester", without looping? (i can use rbind in a for loop, but is rather slow)
thanks for your help,
Remko Duursma
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