Integrate(dnorm) with different mean and standard deviation help
On 2012-07-23 19:48, Pascal Oettli wrote:
Hello, Maybe the following could help:
> f <- function(x) dnorm(x, mean=2, sd=1) > integrate(f, -1.96, 1.96)
0.4840091 with absolute error < 1.4e-12
Or you could note the '...' argument indicated on the help page:
integrate(dnorm, lower = -1.96, upper = 1.96,
mean = 2, sd = 1)
Peter Ehlers
HTH Regards. Le 24/07/2012 11:23, FJ M a ?crit :
I'm trying to provide different parameters to the integrate function for various probability functions. I'm using dnorm as the simplest example here. For instance integrate(dnorm, -1.96, 1.96) produces the correct answer for a normal distribution with mean 0 and standard deviation 1. I've tried two ways to use mean=2.0 and standard deviation 1, but with no luck. The examples follow.
integrate(dnorm, -1.96, 1.96)
0.9500042 with absolute error < 1e-11
mean = 2.0 sd = 1.0 integrate(dnorm, -1.96, 1.96)
0.9500042 with absolute error < 1e-11
integrate(dnorm(mean=2.0,sd=1.0), -1.96, 1.96)
Error in .Internal(dnorm(x, mean, sd, log)) : 'x' is missing Calls: integrate -> match.fun -> dnorm Execution halted How do I change the built in mean=0 and standard deviation=1 for dnorm using integrate? Thanks, Frank Chicago, IL [[alternative HTML version deleted]]
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______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.