Equivalent to matlab ".*" operator in R
It can be simplified a bit, though, as the second operand in the multiplication does not need to be a matrix: y * rep(z,each=3)
On 19 Nov 2014, at 16:24 , Jeff Newmiller <jdnewmil at dcn.davis.ca.us> wrote:
When your matrices are the same size, the "*" operator does what you want. The problem is that you have to make a conforming version of z before you can use that operator.
y*matrix(rep(z,3),ncol=2,byrow=TRUE)
or
y*matrix(rep(z,each=3),ncol=2)
To interpret this, just keep in mind that matrices are folded vectors in R... every matrix can be thought of as a linear vector of columnwise data with dimension attributes.
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On November 19, 2014 6:43:55 AM PST, "Ruima E." <ruimaximo at gmail.com> wrote:
Thank you Chel Hee. Isn't there a simpler way to do so? On Wed, Nov 19, 2014 at 3:35 PM, Chel Hee Lee <chl948 at mail.usask.ca> wrote:
y = matrix(cbind(c(0, 0.5, 1),c(0, 0.5, 1)),ncol=2) z = matrix(c(12, -6),ncol=2) t(apply(y, 1, function(x) x*z))
[,1] [,2] [1,] 0 0 [2,] 6 -3 [3,] 12 -6 I hope this helps. Chel Hee Lee On 14-11-19 08:22 AM, Ruima E. wrote:
Hi, I have this: y = matrix(cbind(c(0, 0.5, 1),c(0, 0.5, 1)),ncol=2) z = matrix(c(12, -6),ncol=2) In matlab I would do this
y .* x
I would get this in matlab
ans
0 -0
6 -3
12 -6
What is the equivalent in R?
Thanks
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