lapply to list of variables

Hi:

Here's another way of doing this on the simplified version of your example:

L <- vector('list', 3)      # initialize a list of three components
## populate it
for(i in seq_along(L)) L[[i]] <- rnorm(20, 10, 3)
## name the components
names(L) <- c('Monday', 'Tuesday', 'Wednesday')
## replace values <= 10 with NA
lapply(L, function(x) replace(x, x <= 10, NA)

If you have a large number of atomic objects, you could create a
vector of the object names, make a list out of them (e.g., L <-
list(objnames)) and then mimic the lapply() as above. replace() only
works on vectors, though - Uwe's solution is more general.

HTH,
Dennis

Hi

Can someone help me with this?

How can I apply a function to a list of variables.

something like this


listvar=list("Monday","Tuesday","Wednesday")
func=function(x){x[which(x<=10)]=NA}

lapply(listvar, func)

were
Monday=[213,56,345,33,34,678,444]
Tuesday=[213,56,345,33,34,678,444]
...

in my case I have a neverending list of vectors.

Thanks!

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