how to 'get' an object that is part of a list
Is this what you are looking for:
my.length.2 <- function(...) {
+ f <- function(nm, val) length(val) + mapply(f, make.names(as.list(match.call()[-1])), list(...)) + }
my.length.2(xx, xx$b)
xx xx.b 2 5
On 12/24/06, jim holtman <jholtman at gmail.com> wrote:
use 'eval' and 'parse'
xx
$a [1] 1 2 3 4 5 $b [1] "a" "b" "c" "d" "e"
eval(parse(text='xx$a'))
[1] 1 2 3 4 5
So that way you can pass in the character string and then 'parse' it. On 12/24/06, Christos Hatzis <christos at nuverabio.com> wrote:
This might be an trivial thing but I am stuck. Consider: xx <- list(a=1:5, b=letters[1:5]) Although object xx is accessible through its name, how can object xx$b be accessed similarly through its name?
get("xx")
$a [1] 1 2 3 4 5 $b [1] "a" "b" "c" "d" "e"
get("xx$b")
Error in get(x, envir, mode, inherits) : variable "xx$b" was not found
get("xx")$b will not work in my case because it will probably require
parsing to make it work within a function. E.g.
my.length <- function(...) {
names <- as.character(substitute(list(...)))[-1]
sapply(names, FUN=function(x){y <- get(x); length(y)})
}
my.length(xx)
xx 2
my.length(xx$a)
Error in get(x, envir, mode, inherits) : variable "xx$a" was not found
my.length(xx$a, xx$b)
Error in get(x, envir, mode, inherits) : variable "xx$a" was not found Thank you. Christos Hatzis, Ph.D. Nuvera Biosciences, Inc. 400 West Cummings Park Suite 5350 Woburn, MA 01801 Tel: 781-938-3830 www.nuverabio.com
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--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?
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______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.