Odp: ^ operator

Not in this case (see below), though of course in general "-" takes
 precedence over "^", so, for example, in the expression

  -2^(1/3)

 the "-" is applied first, giving (-2); and then "^" is applied
 next, giving (-2)^(1/3). There is a work-round (see below).

Hmm.. I may be doing something wrong, but from here it looks to be the
opposite.

-2^(1/3); -(2)^(1/3); -(2^(1/3));

[1] -1.2599
[1] -1.2599
[1] -1.2599

(-2)^(1/3)

[1] NaN

The results don't change when switching from the unary minus.

0-2^(1/3); 0-(2)^(1/3); 0-(2^(1/3));

[1] -1.2599
[1] -1.2599
[1] -1.2599

It seems to me that in this example "^" is applied first, and "-"
second. There is also this fortune entry.

fortune("unary")

Thomas Lumley: The precedence of ^ is higher than that of unary minus.
It may be surprising,
[...]
Herv? Pag?s: No, it's not surprising. At least to me... In the country
where I grew up, I've
been teached that -x^2 means -(x^2) not (-x)^2.
   -- Thomas Lumley and Herv? Pag?s (both explaining that operator
precedence is working
      perfectly well)
      R-devel (January 2006)


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