regexpr - ignore all special characters and punctuation in a string
I think I found a partial answer: str_replace_all(x, "[[:punct:]]", " ") On Mon, Apr 20, 2015 at 9:59 AM, Dimitri Liakhovitski
<dimitri.liakhovitski at gmail.com> wrote:
Hello! Please point me in the right direction. I need to match 2 strings, but focusing ONLY on characters, ignoring all special characters and punctuation signs, including (), "", etc.. For example: I want the following to return: TRUE "What a nice day today! - Story of happiness: Part 2." == "What a nice day today: Story of happiness (Part 2)" -- Thank you! Dimitri Liakhovitski
Dimitri Liakhovitski