Message-ID: <AANLkTinHsDGq99TDeZHaHeYUducr2yG90HSY=SKP4qsn@mail.gmail.com>
Date: 2010-12-23T16:28:30Z
From: Hadley Wickham
Subject: Writing a single output file
In-Reply-To: <AANLkTikmewLa1tYvkg_URT5gFeW5Bs-15nGrqxf6=wC1@mail.gmail.com>
>> input <- do.call(rbind, lapply(fileNames, function(.name){
> + ? ? .data <- read.table(.name, header = TRUE, as.is = TRUE)
> + ? ? # add file name to the data
> + ? ? .data$file <- .name
> + ? ? .data
> + }))
You can simplify this a little with plyr:
fileNames <- list.files(pattern = "file.*.csv")
names(fileNames) <- fileNames
input <- ldply(fileNames, read.table, header = TRUE, as.is = TRUE)
Hadley
--
Assistant Professor / Dobelman Family Junior Chair
Department of Statistics / Rice University
http://had.co.nz/