Message-ID: <Pine.LNX.4.61.0505111831190.3399@gannet.stats>
Date: 2005-05-11T17:32:38Z
From: Brian Ripley
Subject: simplify loop
In-Reply-To: <3f87cc6d05051110054d65813a@mail.gmail.com>
It is, backwards, a cumulative product so you could use cumprod.
On Wed, 11 May 2005, Omar Lakkis wrote:
> Is there a way to implement this faster than doing it in a loop.
>
> for (i in length(settle)-1:1) {
> settle[i] = settle[i+1]/(1 + settle.pct[i+1])
> }
>
> I want to guarantee that i+1 is calculated before i
>
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--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
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