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Calculate mileage at each 'faildate'

PIKAL Petr 
Hi

I wonder what do you want to do with intended output. You can get required numbers by

lll <- split(simD, simD$ID)
lapply(lll, function(x) c(min(x[, "MILEAGE"]), diff(x[,"MILEAGE"])))

$A
[1] 21548  1030   290   786

$B
[1] 30245  1903  1980  1751  3995   251

Then pad it with NA

max.l<-max(sapply(res, length))
res2<-lapply(res, function(x) c(x, rep(NA, max.l-length(x))))

$A
[1] 21548  1030   290   786    NA    NA

$B
[1] 30245  1903  1980  1751  3995   251
[,1] [,2] [,3] [,4] [,5] [,6]
A 21548 1030  290  786   NA   NA
B 30245 1903 1980 1751 3995  251
After that you should combine it with required values from first data frame and of course you need to name new columns e.g. by loop.

If you had it as a list you could work with it easily by R functions or convert it back to your data frame
data.frame(ldply(lll, data.frame), fMileage=unlist(res))
   .id ID   PRODDATE   FAILDATE MILEAGE fMileage
A1   A  A 2010-02-15 2011-03-20   21548    21548
A2   A  A 2010-02-15 2011-03-21   22578     1030
A3   A  A 2010-02-15 2011-03-24   22868      290
A4   A  A 2010-02-15 2011-03-25   23654      786
B1   B  B 2010-02-24 2010-08-23   30245    30245
B2   B  B 2010-02-24 2010-09-23   32148     1903
B3   B  B 2010-02-24 2010-09-24   34128     1980
B4   B  B 2010-02-24 2010-10-23   35879     1751
B5   B  B 2010-02-24 2010-11-23   39874     3995
B6   B  B 2010-02-24 2010-12-23   40125      251

Cheers
Petr
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Abhinaba Roy Calculate mileage at each 'faildate' Aug 10 PIKAL Petr Calculate mileage at each 'faildate' Aug 10