sapply question
Go back and reread the section about the scoping of variables and that functions do not have side effects; they only return values. You are changinga "local" copy of df1 within the function which is returning the changed values to df3. On Wed, Jul 11, 2012 at 7:36 PM, Charles Stangor
<cstangor at charlesstangor.com> wrote:
Why does this sapply code change df3 but not df1?
Thanks
df1 <- read.table(text="
cola colb colc cold cole
1 NA 5 9 NA 17
2 NA 6 NA 14 NA
3 3 NA 11 15 19
4 4 8 12 NA 20
", header=TRUE)
df2 <-df1*2
df1
df2
df3 <-sapply(names(df1),function(x) {df1[[x]]<- df2[[x]]})
df1
df3
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