Message-ID: <23663549.post@talk.nabble.com>
Date: 2009-05-22T02:32:13Z
From: Ben Bolker
Subject: Behavior of seq with vector from
In-Reply-To: <3BAD818D9407B043817CC6D89ABA14EC032B85B0@MLNYC20MB051.amrs.win.ml.com>
Rowe, Brian Lee Yung (Portfolio Analytics) wrote:
>
> Hello,
>
> I want to use seq with multiple from values and am getting unexpected
> (to me) behavior. I'm wondering if this behavior is intentional or not.
>
>> seq(2, by=3, length.out=4)
> [1] 2 5 8 11
>
>> seq(3, by=3, length.out=4)
> [1] 3 6 9 12
>
> Now if I want the combined sequence, I thought I could pass in c(2,3),
> and I get:
>> seq(c(2,3), by=3, length.out=8)
> [1] 2 6 8 12 14 18 20 24
>
> However, the result is not what I expected (i.e. what I wanted):
> [1] 2 3 5 6 8 9 11 12
>
> It seems that this is a consequence of vector recycling during the
> summation in seq.default:
> if (missing(to)) from + (0L:(length.out - 1L)) * by
>
> To get the value I want, I am using the following code:
>> sort(as.vector(apply(array(c(2,3)), 1, seq, by=3,length.out=4)))
> [1] 2 3 5 6 8 9 11 12
>
> So two questions:
> 1. Is seq designed/intended to be used with a vector from argument, and
> is this the desired behavior?
> 2. If so, is there a cleaner way of implementing what I want?
>
> Thanks,
> Brian
>
>
Don't know if this is "cleaner" or not.
It may be a little bit too tricky.
c(outer(2:3,seq(0,by=3,length.out=4),"+"))
Can compress your example slightly:
c(t(apply(matrix(2:3), 1, seq, by=3,length.out=4)))
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