On 5/11/2016 2:23 PM, Jan Kacaba wrote:
Here is my attempt at function which computes margins from positions.
require("stringr")
require("dplyr")
ends<-seq(10,100,8) # end margins
test_string<-"Lorem ipsum dolor sit amet, consectetuer adipiscing
elit. Aliquam in lorem sit amet leo accumsan lacinia."
sekoj=function(ends){
l_ends<-length(ends)
begs=vector(mode="integer",l_ends)
begs[1]=1
for (i in 2:(l_ends)){
begs[i]<-ends[i-1]+1
}
margs<-rbind(begs,ends)
margs<-cbind(margs,c(ends[l_ends]+1,-1))
#rownames(margs)<-c("beg","end")
return(margs)
}
margins<-sekoj(ends)
str_sub(test_string,margins[1,],margins[2,]) %>% print
Code to run in browser:
http://www.r-fiddle.org/#/fiddle?id=rVmNVxDV
2016-05-11 23:12 GMT+02:00 Bert Gunter <bgunter.4567 at gmail.com>:
Dunno -- but you might have a look at Hadley Wickham's 'stringr' package:
https://cran.r-project.org/web/packages/stringr/stringr.pdf
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Wed, May 11, 2016 at 1:12 PM, Jan Kacaba <jan.kacaba at gmail.com> wrote:
Dear R-help
I would like to split long string at specified precomputed positions.
'substring' needs beginings and ends. Is there a native function which
accepts positions so I don't have to count second argument?
For example I have vector of possitions pos<-c(5,10,19). Substring
needs input first=c(1,6,11) and last=c(5,10,19). There is no problem
to write my own function. Just asking.
Derek
I think you can simply this. just create a function (I'll call it begs)
to compute the beginning positions.
begs <- function(x) c(0,x[-length(x)])+1
Then, then use that function in your call to str_sub
str_sub(test_string,begs(ends),ends) %>% print