another basic ?
jimi adams <adams.644 at osu.edu> writes:
i am sure that there is a simple solution that i am just overlooking, but there is no logical test for = there is one for != and >,<, >=, <=... what do i do if i need to check if something IS EQUAL
Double it: ==
or is there an easy way, in working with a matrix of size n x 3, to sort the matrix by one of the columns? specifically what i am trying to do is i have a matrix with individual and group labels that is randomly generated, and is by default sorted by the individual labels ( column 1) and i want them to be organized into unique group labels (comlumn 2) thanks
m[order(m[,2]),]
O__ ---- Peter Dalgaard Blegdamsvej 3 c/ /'_ --- Dept. of Biostatistics 2200 Cph. N (*) \(*) -- University of Copenhagen Denmark Ph: (+45) 35327918 ~~~~~~~~~~ - (p.dalgaard at biostat.ku.dk) FAX: (+45) 35327907 -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._