Find the sign
if (x*y>0) {...}
On Mon, Jan 24, 2011 at 1:27 PM, Rainer Schuermann
<Rainer.Schuermann at gmx.net> wrote:
On Monday, January 24, 2011 07:18:03 pm Alaios wrote:
Hello :) I wanted to right an expression to check when x and y have the same sign and I wrote the following: ?if ((x<0 && y<0) || (x>0 && y>0)) which looks pretty ugly to me. Can you please suggest me a better way for that? Regards Alex
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
if( sign( x ) == sign( y ) )
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.