apply problem
On Sun, 17 Mar 2002 ggrothendieck at yifan.net wrote:
apply(iris3,1,function(x)identical(x,iris3[1,]))
1 2 3 FALSE FALSE FALSE What's wrong here?
[snip]
OK. Efficiency aside,I believe it would still be nice to have this ability for compactness. Here are some ideas:
How about:
sapply( seq(along=iris3[,1]), function(x,y) identical(y[x,], iris3[1,]),
+ y=iris3) [1] TRUE FALSE FALSE
Greg Snow, PhD Office: 223A TMCB Department of Statistics Phone: (801) 378-7049 Brigham Young University Dept.: (801) 378-4505 Provo, UT 84602 email: gls at byu.edu -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-help-request at stat.math.ethz.ch _._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._._