rounding problem
all.equal is what i need, many thanks to help me
baptiste auguie-2 wrote:
Hi, you probably want to use ?all.equal instead of "==" I couldn't run your example, though Hope this helps, baptiste On 27 Feb 2009, at 10:32, Peterko wrote:
hi i am creating some variables from same data, but somewhere is
different
rouding.
look:
P = abs(fft(d.zlato)/480)^2
hladane= sort(P,decreasing=T)[1:10]/480
pozicia=c(0,0,0,0,0)
for (j in 1:5){ for (i in 2:239){
if (P[i]/480==hladane[2*j-1]){pozicia[j]=i-1}}}
period=479/pozicia
P[2]/334
[1] 0.0001279107
hladane[1]
[1] 0.0001279107
P[2]/334==hladane[1]
[1] FALSE
abs(P[2]/334 - hladane[1]) < 0.0000001
[1] TRUE It is possible to avoid it ? I know in this exam i can use 2x if to eliminate this rouding, but i need to fix it in general. -- View this message in context: http://www.nabble.com/rounding-problem-tp22243179p22243179.html Sent from the R help mailing list archive at Nabble.com.
______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
_____________________________ Baptiste Augui? School of Physics University of Exeter Stocker Road, Exeter, Devon, EX4 4QL, UK Phone: +44 1392 264187 http://newton.ex.ac.uk/research/emag ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
View this message in context: http://www.nabble.com/rounding-problem-tp22243179p22243567.html Sent from the R help mailing list archive at Nabble.com.