Data manipulation in a data.frame
This merely translates the matrix multiplication I used into explicit arithmetic! Nor does it generalize without extra manipulation to get the correct arithmetic expression. -- Bert Bert Gunter Genentech Nonclinical Biostatistics (650) 467-7374 "Data is not information. Information is not knowledge. And knowledge is certainly not wisdom." H. Gilbert Welch
On Fri, Feb 21, 2014 at 9:25 AM, arun <smartpink111 at yahoo.com> wrote:
Hi IOanna,
Do you have rows with multiple '1's? If not, you could also try:
A$Variable <- c("none",names(A)[-1])[1+with(A,B+2*C+3*D)]
A.K.
On Friday, February 21, 2014 4:44 AM, ioanna ioannou <ii54250 at msn.com> wrote:
Thank you very much. One further question.
Assuming that for some points there is no classification for example:
A<-data.frame(A=c(10,100,1000,30,50,60,300,3),
B=c(0,1,1,1,0,0,0,0),
C=c(0,0,0,0,1,1,0,0),
D=c(1,0,0,0,0,0,1,0))
Is there an easy way to introduce an extra none option in the variable?
A<-data.frame(A=c(10,100,1000,30,50,60,300,3),
B=c(0,1,1,1,0,0,0,0),
C=c(0,0,0,0,1,1,0,0),
D=c(1,0,0,0,0,0,1,0),
Variable=c(D,B,B,B,C,C,D,none))
Thanks in advance,
IOanna
-----Original Message-----
From: arun [mailto:smartpink111 at yahoo.com]
Sent: 21 February 2014 00:19
To: r-help at r-project.org
Cc: ioanna ioannou
Subject: Re: [R] Data manipulation in a data.frame
Also,
rownames(which(t(!!A[,-1]),arr.ind=TRUE))
A.K.
On Thursday, February 20, 2014 6:48 PM, arun <smartpink111 at yahoo.com> wrote:
Hi,
May be this helps:
A$Variable <- rep(colnames(A[,-1]),nrow(A))[t(!!A[,-1])]
A.K.
On Thursday, February 20, 2014 5:55 PM, ioanna ioannou <ii54250 at msn.com>
wrote:
Hello,
Assuming that I have a data frame
A<-data.frame(A=c(10,100,1000,30,50,60,300),
B=c(0,1,1,1,0,0,0),
C=c(0,0,0,0,1,1,0),
D=c(1,0,0,0,0,0,1))
What I would like is to introduce a new column Variable such that:
A<-data.frame(A=c(10,100,1000,30,50,60,300),
B=c(0,1,1,1,0,0,0),
C=c(0,0,0,0,1,1,0),
D=c(1,0,0,0,0,0,1),
Variable=c(D,B,B,B,C,C,D))
How can I do it?
Best
IOanna
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