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Message-ID: <1372807838.55277.YahooMailNeo@web142603.mail.bf1.yahoo.com>
Date: 2013-07-02T23:30:38Z
From: arun
Subject: Recoding variables based on reference values in data frame
In-Reply-To: <CAFpPP=zzXSSAUhZv36K5Qg7jFVyqHaY6LHWFQWPSb97MtfWNDQ@mail.gmail.com>

Hi,
May be this helps:
Kgeno<- read.table(text="
SNP_ID SNP1 SNP2 SNP3 SNP4
Maj_Allele C G? C? A
Min_Allele T A T G? 
ID1 CC??? GG??? CT??? AA
ID2 CC??? GG??? CC AA
ID3 CC??? GG nc? AA
ID4? _? _? _? _ 
ID5 CC??? GG??? CC??? AA
ID6 CC??? GG??? CC? AA
ID7 CC??? GG??? CT??? AA
ID8 _ _ _ _? 
ID9 CT??? GG? CC AG
ID10 CC??? GG??? CC??? AA
ID11 CC??? GG??? CT??? AA
ID12 _ _ _ _? 
ID13 CC??? GG??? CC??? AA
",sep="",header=TRUE,stringsAsFactors=FALSE)

library(stringr)
library(car)

fun1<- function(x){
?MajMin<- paste0(x[1],x[2])
?MajMaj<-str_dup(x[1],2)
?MinMin<-str_dup(x[2],2)
?recode(x,"'nc'=NA;'_'=NA;MajMaj=0;MajMin=1;MinMin=2")}
sapply(Kgeno[,-1],fun1)

#or

?mat1<-sapply(Kgeno[1:2,-1],function(x) {c(str_dup(x,2),paste(x,collapse=""))})[c(1,3,2),]
sapply(seq_len(ncol(Kgeno[,-1])),function(i) {x<-Kgeno[-c(1:2),-1][,i];as.numeric(factor(x,levels=mat1[,i]))-1})


#Speed comparison
KgenoNew<- rbind(Kgeno[c(1:2),-1],sapply(Kgeno[-c(1:2),-1],rep,1e4))
?system.time(res1<- sapply(KgenoNew,fun1))
#?? user? system elapsed 
?#0.672?? 0.000?? 0.674 


system.time({
mat1<-sapply(Kgeno[1:2,-1],function(x) {c(str_dup(x,2),paste(x,collapse=""))})[c(1,3,2),]
res2<- sapply(seq_len(ncol(KgenoNew)),function(i){ x<- KgenoNew[-c(1:2),][,i];as.numeric(factor(x,levels=mat1[,i]))-1})
})
#user? system elapsed 
#? 0.212?? 0.000?? 0.214 
res1New<- res1[-c(1:2),]
res1New1<- as.numeric(res1New)
?dim(res1New1)<- dim(res1New)
identical(res1New1,res2)
#[1] TRUE
A.K.







----- Original Message -----
From: kathleen askland <k.askland at gmail.com>
To: r-help at r-project.org
Cc: 
Sent: Tuesday, July 2, 2013 4:46 PM
Subject: [R] Recoding variables based on reference values in data frame

I'm new to R (previously used SAS primarily) and I have a genetics data
frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3,
...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of
the data is shown below:
? SNP_ID SNP1 SNP2 SNP3 SNP4? Maj_Allele C G? C? A? Min_Allele T A T G? ID1
CC? ?  GG? ?  CT? ?  AA? ? ? ID2 CC? ?  GG? ?  CC AA? ? ? ID3 CC? ?  GG
nc
AA? ? ? ID4 _ _ _ _? ID5 CC? ?  GG? ?  CC? ?  AA? ? ? ID6 CC? ?  GG? ?  CC
? ?  AA? ? ? ID7 CC? ?  GG? ?  CT? ?  AA? ? ? ID8 _ _ _ _? ID9 CT? ?  GG
CC AG? ? ? ID10 CC? ?  GG? ?  CC? ?  AA? ? ? ID11 CC? ?  GG? ?  CT? ?  AA
? ? ? ID12 _ _ _ _? ID13 CC? ?  GG? ?  CC? ?  AA
The name of the data file is Kgeno.
What I would like to do is recode all of the genotype values to standard
integer notation, based on their values relative to the reference rows
(Maj_Allele and Min_Allele). Standard notation sums the total of minor
alleles in the genotype, so values can be 0, 1 or 2.

Here are the changes I want to make:
1. If the genotype= "nc" or '_" then set equal to NA.
2. If genotype value = a character string comprised of two consecutive
major allele values -- c(Maj_Allele, Maj_Allele) -- then set equal to 0.
3. If genotype? value= c(Maj_Allele, Min_Allele) then set equal to 1.
4. If genotype? value = c(Min_Allele, Min_Allele) then set equal to 2.

I've tried the following ifelse processing but get error (Warning: Executed
script did not end with R session at the top-level prompt.? Top-level state
will be restored) and can't seem to fix the code properly. I've counted the
parentheses. Also, not sure if it would execute properly if I could fix it.

# change 'nc' and '_' to NA, else leave as is:
Kgeno[,2] <- ifelse(Kgeno[,2] == "nc", "NA", Kgeno[,2])
Kgeno[,2] <- ifelse(Kgeno[,2] == "_", "NA", Kgeno[,2])

#convert genotype strings in the first data column to numeric values #(two
major alleles=0, 1 minor and 1 major=1, 2 minor alleles=2), else #leave as
is (to preserve NA values).

Kgeno[,2] <-

ifelse(Kgeno[,2] == noquote(paste(as.character(Kgeno[1,2]), as.character(
Kgeno[1,2]), sep=""), 0,

ifelse(Kgeno[,2] == noquote(paste(as.character(Kgeno[1,2]), as.character(
Kgeno[2,2]), sep=""), 1,

ifelse(Kgeno[,2] == noquote(paste(as.character(Kgeno[2,2]), as.character(
Kgeno[2,2]), sep=""), 2,
? ? ? ? ? ? Kgeno[,2])))


Finally, if above code were corrected, this would only change the first
column of data, but I would like to change all 3000+ columns in the same
way.

I would greatly appreciate some suggestions on how to proceed.

Thank you,

Kathleen

---
Kathleen Askland, MD
Assistant Professor
Department of Psychiatry & Human Behavior
The Warren Alpert School of Medicine
Brown University/Butler Hospital

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