New var
As Bert says/implies, "some assembly is required". as.Date() is your friend and you can basically just subtract those to get differences. Also, it seems to me that you are really trying to convert differences to a factor, and then represent the factor using particular dummy variables for successive differences, for use in a linear model of sorts. A combination of cut() and a contrast matrix (see contrasts<-) might be a better structured approach. -pd
On 3 Jun 2017, at 07:13 , Bert Gunter <bgunter.4567 at gmail.com> wrote: Ii is difficult to provide useful help, because you have failed to read and follow the posting guide. In particular: 1. Plain text, not HTML. 2. Use dput() or provide code to create your example. Text printouts such as that which you gave require some work to wrangle into into an example that we can test. Specifically: 3. Have you gone through any R tutorials?-- it sure doesn't look like it. We do expect some effort to learn R before posting. 4. What is the format of your date columns? character, factors, POSIX,...? See ?date-time for details. Note particularly the "difftime" link to obtain intervals. 5. ?ifelse for vectorized conditionals. Also, you might want to explain the context of what you are trying to do. I strongly suspect you shouldn't be doing it at all, but that is just a guess. Be sure to cc your reply to the list, not just to me. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Fri, Jun 2, 2017 at 8:49 PM, Val <valkremk at gmail.com> wrote:
Hi all,
I have a data set with time interval and depending on the interval I want
to create 5 more variables . Sample data below
obs, Start, End
1,2/1/2015, 1/1/2017
2,4/11/2010, 1/1/2011
3,1/4/2006, 5/3/2007
4,10/1/2007, 1/1/2008
5,6/1/2011, 1/1/2012
6,10/15/2004,12/1/2004
First, I want get interval between the start date and end dates
(End-start).
obs, Start , end, datediff
1,2/1/2015, 1/1/2017, 700
2,4/11/2010, 1/1/2011, 265
3,1/4/2006, 5/3/2007, 484
4,10/1/2007, 1/1/2008, 92
5,6/1/2011, 1/1/2012, 214
6,10/15/2004,12/1/2004,47
Second. I want create 5 more variables t1, t2, t3, t4 and t5
The value of each variable is defined as follows
if datediff < 100 then t1=1, t2=t3=t4=t5=-1.
if datediff >= 100 and < 200 then t1=0, t2=1,t3=t4=t5=-1,
if datediff >= 200 and < 300 then t1=0, t2=0,t3=1,t4=t5=-1,
if datediff >= 300 and < 400 then t1=0, t2=0,t3=0,t4=1,t5=-1,
if datediff >= 400 and < 500 then t1=0, t2=0,t3=0,t4=0,t5=1,
if datediff >= 500 then t1=0, t2=0,t3=0,t4=0,t5=0
The complete out put looks like as follow.
obs, start, end, datediff, t1, t2, t3, t4, t5
1, 2/1/2015, 1/1/2017, 700, 0, 0, 0, 0, 0
2, 4/11/2010, 1/1/2011, 265, 0, 0, 1, -1, -1
3, 1/4/2006, 5/3/2007, 484, 0, 0, 0, 0, 1
4, 10/1/2007, 1/1/2008, 92, 1, -1, -1,-1, -1
5 , 6/1/2011, 1/1/2012, 214, 0, 0, 1,-1, -1
6, 10/15/2004, 12/1/2004, 47, 1, -1, -1, -1, -1
Thank you.
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______________________________________________ R-help at r-project.org mailing list -- To UNSUBSCRIBE and more, see https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Peter Dalgaard, Professor, Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Office: A 4.23 Email: pd.mes at cbs.dk Priv: PDalgd at gmail.com