all combinations with replacement
Does the following do what you want? It should
generate all the (unordered) NPart-partitions of Sum
by mapping the output of combn(Sum+NParts-1,NParts-1).
f <- function (Sum, NParts)
{
cm <- combn(Sum + NParts - 1, NParts - 1)
cm <- rbind(cm, Sum + NParts)
if (NParts > 1) {
r <- 2:NParts
cm[r, ] <- cm[r, ] - cm[r - 1, ]
}
t(cm - 1)
}
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-----Original Message----- From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Kehl D?niel Sent: Thursday, April 21, 2011 12:29 PM To: r-help at r-project.org Subject: [R] all combinations with replacement Dear all, is there an easy way to get all possible combinations (?) with replacement. If n=6, k=3, i want something like 0 0 6 0 5 1 0 4 2 0 3 3 0 2 4 . . . 5 0 1 5 1 0 6 0 0 I tried to look at combn() but I could not get this done with it. Thank you in advance: Daniel
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