another question: how to delete one of columes in two ones with high correlation(0.95)
You need dim(cor.matrix)[1] Following might be better instead of a loop, to to get the row ids of a matrix (which(cor.matrix >=0.95) %/% dim(cor.matrix)[1])+1 for column ids use modulus instead of integer divison. (which(cor.matrix >=0.95) %% dim(cor.matrix)[1]) There are probably better ways than this. Nikhil but probably a better way to do this would be
On 6 Nov 2009, at 3:16AM, bbslover wrote:
for(i in 1:(cor.matrix[1]-1))
{
for(j in (i+1):(cor.matrix[2]))
{
if (cor.matrix[i,j]>=0.95)
{
data.f<-data.f[,-i];
i<-i+1
}
}
}