regexp capturing group in R
Try this:
library(gsubfn)
strapply("blah blah start=20080101 end=20090224", "start=(\\d{8})
end=(\\d{8})", c, perl = TRUE)[[1]]
or perhaps just:
strapply("blah blah start=20080101 end=20090224", "\\d{8}", perl = TRUE)[[1]]
On Tue, Feb 24, 2009 at 7:23 PM, <pierre at demartines.com> wrote:
Hello,
Newbie question: how do you capture groups in a regexp in R?
Let's say I have txt="blah blah start=20080101 end=20090224".
I'd like to get the two dates start and end.
In Perl, one would say:
my ($start,$end) = ($txt =~ /start=(\d{8}).*end=(\d{8})/);
I've tried:
txt <- "blah blah start=20080101 end=20090224"
m <- regexpr("start=(\\d{8}).*end=(\\d{8})", filename, perl=T);
dates = substring(filename, m, m+attr(m,"match.length")-1);
but I get the whole matching substring...
Any idea?
~Pierre
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