Upper bands and lower bands
Hi Pedro, If I get the idea, you want a vector of length 7300 starting at 1 and ending at 0. seq(1,0,length.out=7300) Produces such a vector. It seems to me that: seq(1.1,0.05,length.out=7300) produces the upper vector and: seq(0.95,-0.05 length.out=7300) the lower. Then again, I might have the wrong idea big time. Jim
On Fri, Jun 2, 2017 at 6:20 AM, Pedro p?ramo <percentil101 at gmail.com> wrote:
I explain better: I have this percentage z<-1/(n*365) where n=20 so z is 0,000136986 Imagine: a matrix with length(n*365) so that matrix result is resultc( 1, 1-z result previous row-z result previous row-z .... 0) If I plot this is a linear decreasing line I want to plot an upper line wich is 10% higher tan resultc on the first values and then decreasing so that last value will be 0.05. the same in the lower, a line which values are at the beggining a 10% lower and smoothly dreasing values till the last will be 5% lower. Is it posible to make thins bands exponencially with a code? 2017-06-01 20:20 GMT+02:00 Pedro p?ramo <percentil101 at gmail.com>:
Hi all I want to add a band of fluctuaci?n (exponential decreading) to a linear deacrecing values Imagine: I have a matrix like c(10,9,8,7,6,5,4,3,2,1) The thing is I want two new lines so that the m?ximum value of the new colum on the m?ximum is from 10% to 5% higher and the same lower for the m?nimum the final two matix will be something like c(10+0.10*10,9+0.089*9,8+0.075*8.....,1+0.05*1) c(10-0.10*10,9-0.09*9,8-0.075*8.....,1-0.05*1) What I?m looking for is a function tu calculate de "values, weights" so that including the 10% and 5% and the nunmber of decreasing values, in this case n=10, calculates de smotth weigths. I don?t know if I have expalined well so thar finally putting initial value final and periods I can find a matrix like g(0.1,0.89,0.79,0.075,...,0.05) Exists something like that?
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