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Normal distribution with R

Hi James
its just simple calculus, since with
q90<-qnorm(.9,me,sd)
q10<-qnorm(.1,me,sd)

mean<-(q90+q10)/2    # the normal distribution is symmetric around the mean
sd<-(q90-q10)/ (qnorm(.9)-qnorm(.1)) #  between 10th and 90th are 
qnorm(.9)-qnorm(.1)=2.563103sds

hth.

guox at ucalgary.ca schrieb: