RandomForest question
From: Uwe Ligges Arne.Muller at sanofi-aventis.com wrote:
Hello, I'm trying to find out the optimal number of splits (mtry parameter) for a randomForest classification. The classification is binary and there are 32 explanatory variables (mostly factors with each up to 4 levels but also some numeric variables) and 575 cases. I've seen that although there are only 32 explanatory variables the best classification performance is reached when choosing
mtry=80. How
is it possible that more variables can used than there are
in columns
the data frame?
If some of the variables are factors, dummy variables are generated and you get a larger number of variables in the later process.
No, unless the OP is using the formula interface with a version of the package from two years or so ago. We got the first formula interface by copying and modifying the one for svm() in e1071, and forgot the fact that SVM needs that for dealing with factors, but not trees (especially not how the underlying RF code handles them). This has been correctly long ago. Cheers, Andy
Uwe Ligges
thanks for your help + kind regards, Arne [[alternative HTML version deleted]]
______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html