long format with reshape

HI,

You could use:
library(reshape)
?res<-melt(dat,id.var=c("region","state"))
names(res)[3:4]<-c("species","presence")
res<-res[rev(order(res$region,res$state)),]
?row.names(res)<- 1:nrow(res)
?res
? #? region state? species presence
#1?? sydney?? nsw species3??????? 1
#2?? sydney?? nsw species2??????? 1
#3?? sydney?? nsw species1??????? 0
#4 canberra?? act species3??????? 0
#5 canberra?? act species2??????? 1
#6 canberra?? act species1??????? 1
A.K.

----- Original Message -----
From: Daisy Englert Duursma <daisy.duursma at gmail.com>
To: "r-help at R-project.org" <r-help at r-project.org>
Cc: 
Sent: Thursday, January 24, 2013 5:06 AM
Subject: [R] long format with reshape

Hello,

I tried using reshape to rearrange my data to long format but I could
not get the output the table they way I wanted it. Anyway I came up
with a hack that does works, but I still would like to know if I can
do it with reshape.

Here is my code and a dummy set of data. It returns the data in the
format I would like it.

dat <- read.table(text="region state species1 species2 species3
? ? ? ? ? ? ? ? ? ? ? ? sydney nsw 0 1 1
? ? ? ? ? ? ? ? ? ? ? ? canberra act 1 1 0", header=T)

nonspecvars <- c("region","state")

dats <- split(dat, 1:nrow(dat))
dat2 <- lapply(dats,function(x){

? datspec <- x[,-match(nonspecvars,names(x))]
? specnames <- names(datspec)
? presence <- unname(unlist(datspec))

? x2 <- x[rep(1,length(specnames)),match(nonspecvars,names(x))]
? x2$species <- specnames
? x2$presence <- presence
? return(x2)

})

do.call(rbind, dat2)

Cheers,
Daisy

long format with reshape

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