Message-ID: <loom.20081221T153614-458@post.gmane.org>
Date: 2008-12-21T15:43:40Z
From: oliver
Subject: Dataframe help
Rajasekaramya <ramya.victory <at> gmail.com> writes:
>
>
> Hi there,
>
> I have a dataframe length.unique.info
> > length.unique.info
> abc 12 345
> def 16 550
> lmn 6 600
> I want those names that fall under the condition (length.unique.info[,2][i]
> <=5 && length.unique.info[,3][i] >=500)
[...]
Hello,
late answer, but I just looked in the archive...
...and found your question.
Maybe it's too long ago, but as I has some time for and fun with it,
here a way how to achieve it:
intersect( which(mydf[,2] <=5 ), which( mydf[,3] >= 500))
This will result in integer(0), which means, no matching data found.
intersect( which(mydf[,2] <=8 ), which( mydf[,3] >= 500))
would bring you 3 as an answer.
This is the index 3, which means third row does match.
So, you dont need a loop, which I assume you would like to use,
when using i as an index (maybe in the range 1:nrow(length.unique.info).
Ciao,
Oliver