How to convert 3-digits hours
Wonjae Lee wrote:
strptime('20110101 0900',"%Y%m%d %H%M")
[1] "2011-01-01 09:00:00"
strptime('20110101 900',"%Y%m%d %H%M")
[1] NA If I have a 3-digit hour like '900', please show me how to convert it to 09:00:00.
d = c('20110101 900', '20110101 1900')
d1= gsub(" (\\d\\d\\d)$"," 0\\1",d)
strptime(d1,"%Y%m%d %H%M")
Dieter
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